前阵子突然刷到这个命令seq,可以用来生成一堆有序的数。
生成速度还挺快的
查看帮助
seq --help
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┌─[yzf@sparrow] - [/mnt/c/Users/sparrow] - [2020-05-11 12:47:03]
└─[1] seq --help
Usage: seq [OPTION]... LAST
or: seq [OPTION]... FIRST LAST
or: seq [OPTION]... FIRST INCREMENT LAST
Print numbers from FIRST to LAST, in steps of INCREMENT.
Mandatory arguments to long options are mandatory for short options too.
-f, --format=FORMAT use printf style floating-point FORMAT
-s, --separator=STRING use STRING to separate numbers (default: \n)
-w, --equal-width equalize width by padding with leading zeroes
--help display this help and exit
--version output version information and exit
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基本使用
seq 20生成1~20的数，每个一行
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┌─[yzf@sparrow] - [/mnt/c/Users/sparrow] - [2020-05-11 01:00:56]
└─[0] seq 20
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seq 10 20生成10~20的数，每个一行
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┌─[yzf@sparrow] - [/mnt/c/Users/sparrow] - [2020-05-11 01:01:13]
└─[130] seq 10 20
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seq 10 2 20生成10~20的数，步长为2，每个一行
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┌─[yzf@sparrow] - [/mnt/c/Users/sparrow] - [2020-05-11 01:02:36]
└─[0] seq 10 2 20
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-s 指定分隔符
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┌─[yzf@sparrow] - [/mnt/c/Users/sparrow] - [2020-05-11 01:05:32]
└─[0] seq -s + 1 10
1+2+3+4+5+6+7+8+9+10
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有意思的是我在termux上直接-s*就能指定*号为分隔符。但是在wsl上需要加\转义
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┌─[yzf@sparrow] - [/mnt/c/Users/sparrow] - [2020-05-11 01:05:21]
└─[1] seq -s\* 1 10
1*2*3*4*5*6*7*8*9*10
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-f 指定输出格式
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┌─[yzf@sparrow] - [/mnt/c/Users/sparrow] - [2020-05-11 01:10:40]
└─[0] seq -f "int value_%-1g =1;" 1 5
int value_1 =1;
int value_2 =1;
int value_3 =1;
int value_4 =1;
int value_5 =1;
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%g为默认，%kg控制数字前后的格式
-w控制位数等宽
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┌─[yzf@sparrow] - [/mnt/c/Users/sparrow] - [2020-05-11 01:13:36]
└─[130] seq -w 98 101
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099
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101
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